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6p^2+2p-104=0
a = 6; b = 2; c = -104;
Δ = b2-4ac
Δ = 22-4·6·(-104)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-50}{2*6}=\frac{-52}{12} =-4+1/3 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+50}{2*6}=\frac{48}{12} =4 $
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